Optimal. Leaf size=449 \[ -\frac{a d \sinh \left (c-\frac{\sqrt{-a} d}{\sqrt{b}}\right ) \text{Chi}\left (x d+\frac{\sqrt{-a} d}{\sqrt{b}}\right )}{4 b^3}-\frac{a d \sinh \left (\frac{\sqrt{-a} d}{\sqrt{b}}+c\right ) \text{Chi}\left (\frac{\sqrt{-a} d}{\sqrt{b}}-d x\right )}{4 b^3}+\frac{3 \sqrt{-a} \cosh \left (\frac{\sqrt{-a} d}{\sqrt{b}}+c\right ) \text{Chi}\left (\frac{\sqrt{-a} d}{\sqrt{b}}-d x\right )}{4 b^{5/2}}-\frac{3 \sqrt{-a} \cosh \left (c-\frac{\sqrt{-a} d}{\sqrt{b}}\right ) \text{Chi}\left (x d+\frac{\sqrt{-a} d}{\sqrt{b}}\right )}{4 b^{5/2}}-\frac{3 \sqrt{-a} \sinh \left (\frac{\sqrt{-a} d}{\sqrt{b}}+c\right ) \text{Shi}\left (\frac{\sqrt{-a} d}{\sqrt{b}}-d x\right )}{4 b^{5/2}}-\frac{3 \sqrt{-a} \sinh \left (c-\frac{\sqrt{-a} d}{\sqrt{b}}\right ) \text{Shi}\left (x d+\frac{\sqrt{-a} d}{\sqrt{b}}\right )}{4 b^{5/2}}+\frac{a d \cosh \left (\frac{\sqrt{-a} d}{\sqrt{b}}+c\right ) \text{Shi}\left (\frac{\sqrt{-a} d}{\sqrt{b}}-d x\right )}{4 b^3}-\frac{a d \cosh \left (c-\frac{\sqrt{-a} d}{\sqrt{b}}\right ) \text{Shi}\left (x d+\frac{\sqrt{-a} d}{\sqrt{b}}\right )}{4 b^3}-\frac{x^3 \cosh (c+d x)}{2 b \left (a+b x^2\right )}+\frac{\sinh (c+d x)}{b^2 d}+\frac{x \cosh (c+d x)}{2 b^2} \]
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Rubi [A] time = 0.859464, antiderivative size = 449, normalized size of antiderivative = 1., number of steps used = 24, number of rules used = 9, integrand size = 19, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.474, Rules used = {5291, 5293, 2637, 5281, 3303, 3298, 3301, 5292, 3296} \[ -\frac{a d \sinh \left (c-\frac{\sqrt{-a} d}{\sqrt{b}}\right ) \text{Chi}\left (x d+\frac{\sqrt{-a} d}{\sqrt{b}}\right )}{4 b^3}-\frac{a d \sinh \left (\frac{\sqrt{-a} d}{\sqrt{b}}+c\right ) \text{Chi}\left (\frac{\sqrt{-a} d}{\sqrt{b}}-d x\right )}{4 b^3}+\frac{3 \sqrt{-a} \cosh \left (\frac{\sqrt{-a} d}{\sqrt{b}}+c\right ) \text{Chi}\left (\frac{\sqrt{-a} d}{\sqrt{b}}-d x\right )}{4 b^{5/2}}-\frac{3 \sqrt{-a} \cosh \left (c-\frac{\sqrt{-a} d}{\sqrt{b}}\right ) \text{Chi}\left (x d+\frac{\sqrt{-a} d}{\sqrt{b}}\right )}{4 b^{5/2}}-\frac{3 \sqrt{-a} \sinh \left (\frac{\sqrt{-a} d}{\sqrt{b}}+c\right ) \text{Shi}\left (\frac{\sqrt{-a} d}{\sqrt{b}}-d x\right )}{4 b^{5/2}}-\frac{3 \sqrt{-a} \sinh \left (c-\frac{\sqrt{-a} d}{\sqrt{b}}\right ) \text{Shi}\left (x d+\frac{\sqrt{-a} d}{\sqrt{b}}\right )}{4 b^{5/2}}+\frac{a d \cosh \left (\frac{\sqrt{-a} d}{\sqrt{b}}+c\right ) \text{Shi}\left (\frac{\sqrt{-a} d}{\sqrt{b}}-d x\right )}{4 b^3}-\frac{a d \cosh \left (c-\frac{\sqrt{-a} d}{\sqrt{b}}\right ) \text{Shi}\left (x d+\frac{\sqrt{-a} d}{\sqrt{b}}\right )}{4 b^3}-\frac{x^3 \cosh (c+d x)}{2 b \left (a+b x^2\right )}+\frac{\sinh (c+d x)}{b^2 d}+\frac{x \cosh (c+d x)}{2 b^2} \]
Antiderivative was successfully verified.
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Rule 5291
Rule 5293
Rule 2637
Rule 5281
Rule 3303
Rule 3298
Rule 3301
Rule 5292
Rule 3296
Rubi steps
\begin{align*} \int \frac{x^4 \cosh (c+d x)}{\left (a+b x^2\right )^2} \, dx &=-\frac{x^3 \cosh (c+d x)}{2 b \left (a+b x^2\right )}+\frac{3 \int \frac{x^2 \cosh (c+d x)}{a+b x^2} \, dx}{2 b}+\frac{d \int \frac{x^3 \sinh (c+d x)}{a+b x^2} \, dx}{2 b}\\ &=-\frac{x^3 \cosh (c+d x)}{2 b \left (a+b x^2\right )}+\frac{3 \int \left (\frac{\cosh (c+d x)}{b}-\frac{a \cosh (c+d x)}{b \left (a+b x^2\right )}\right ) \, dx}{2 b}+\frac{d \int \left (\frac{x \sinh (c+d x)}{b}-\frac{a x \sinh (c+d x)}{b \left (a+b x^2\right )}\right ) \, dx}{2 b}\\ &=-\frac{x^3 \cosh (c+d x)}{2 b \left (a+b x^2\right )}+\frac{3 \int \cosh (c+d x) \, dx}{2 b^2}-\frac{(3 a) \int \frac{\cosh (c+d x)}{a+b x^2} \, dx}{2 b^2}+\frac{d \int x \sinh (c+d x) \, dx}{2 b^2}-\frac{(a d) \int \frac{x \sinh (c+d x)}{a+b x^2} \, dx}{2 b^2}\\ &=\frac{x \cosh (c+d x)}{2 b^2}-\frac{x^3 \cosh (c+d x)}{2 b \left (a+b x^2\right )}+\frac{3 \sinh (c+d x)}{2 b^2 d}-\frac{\int \cosh (c+d x) \, dx}{2 b^2}-\frac{(3 a) \int \left (\frac{\sqrt{-a} \cosh (c+d x)}{2 a \left (\sqrt{-a}-\sqrt{b} x\right )}+\frac{\sqrt{-a} \cosh (c+d x)}{2 a \left (\sqrt{-a}+\sqrt{b} x\right )}\right ) \, dx}{2 b^2}-\frac{(a d) \int \left (-\frac{\sinh (c+d x)}{2 \sqrt{b} \left (\sqrt{-a}-\sqrt{b} x\right )}+\frac{\sinh (c+d x)}{2 \sqrt{b} \left (\sqrt{-a}+\sqrt{b} x\right )}\right ) \, dx}{2 b^2}\\ &=\frac{x \cosh (c+d x)}{2 b^2}-\frac{x^3 \cosh (c+d x)}{2 b \left (a+b x^2\right )}+\frac{\sinh (c+d x)}{b^2 d}-\frac{\left (3 \sqrt{-a}\right ) \int \frac{\cosh (c+d x)}{\sqrt{-a}-\sqrt{b} x} \, dx}{4 b^2}-\frac{\left (3 \sqrt{-a}\right ) \int \frac{\cosh (c+d x)}{\sqrt{-a}+\sqrt{b} x} \, dx}{4 b^2}+\frac{(a d) \int \frac{\sinh (c+d x)}{\sqrt{-a}-\sqrt{b} x} \, dx}{4 b^{5/2}}-\frac{(a d) \int \frac{\sinh (c+d x)}{\sqrt{-a}+\sqrt{b} x} \, dx}{4 b^{5/2}}\\ &=\frac{x \cosh (c+d x)}{2 b^2}-\frac{x^3 \cosh (c+d x)}{2 b \left (a+b x^2\right )}+\frac{\sinh (c+d x)}{b^2 d}-\frac{\left (3 \sqrt{-a} \cosh \left (c-\frac{\sqrt{-a} d}{\sqrt{b}}\right )\right ) \int \frac{\cosh \left (\frac{\sqrt{-a} d}{\sqrt{b}}+d x\right )}{\sqrt{-a}+\sqrt{b} x} \, dx}{4 b^2}-\frac{\left (a d \cosh \left (c-\frac{\sqrt{-a} d}{\sqrt{b}}\right )\right ) \int \frac{\sinh \left (\frac{\sqrt{-a} d}{\sqrt{b}}+d x\right )}{\sqrt{-a}+\sqrt{b} x} \, dx}{4 b^{5/2}}-\frac{\left (3 \sqrt{-a} \cosh \left (c+\frac{\sqrt{-a} d}{\sqrt{b}}\right )\right ) \int \frac{\cosh \left (\frac{\sqrt{-a} d}{\sqrt{b}}-d x\right )}{\sqrt{-a}-\sqrt{b} x} \, dx}{4 b^2}-\frac{\left (a d \cosh \left (c+\frac{\sqrt{-a} d}{\sqrt{b}}\right )\right ) \int \frac{\sinh \left (\frac{\sqrt{-a} d}{\sqrt{b}}-d x\right )}{\sqrt{-a}-\sqrt{b} x} \, dx}{4 b^{5/2}}-\frac{\left (3 \sqrt{-a} \sinh \left (c-\frac{\sqrt{-a} d}{\sqrt{b}}\right )\right ) \int \frac{\sinh \left (\frac{\sqrt{-a} d}{\sqrt{b}}+d x\right )}{\sqrt{-a}+\sqrt{b} x} \, dx}{4 b^2}-\frac{\left (a d \sinh \left (c-\frac{\sqrt{-a} d}{\sqrt{b}}\right )\right ) \int \frac{\cosh \left (\frac{\sqrt{-a} d}{\sqrt{b}}+d x\right )}{\sqrt{-a}+\sqrt{b} x} \, dx}{4 b^{5/2}}+\frac{\left (3 \sqrt{-a} \sinh \left (c+\frac{\sqrt{-a} d}{\sqrt{b}}\right )\right ) \int \frac{\sinh \left (\frac{\sqrt{-a} d}{\sqrt{b}}-d x\right )}{\sqrt{-a}-\sqrt{b} x} \, dx}{4 b^2}+\frac{\left (a d \sinh \left (c+\frac{\sqrt{-a} d}{\sqrt{b}}\right )\right ) \int \frac{\cosh \left (\frac{\sqrt{-a} d}{\sqrt{b}}-d x\right )}{\sqrt{-a}-\sqrt{b} x} \, dx}{4 b^{5/2}}\\ &=\frac{x \cosh (c+d x)}{2 b^2}-\frac{x^3 \cosh (c+d x)}{2 b \left (a+b x^2\right )}+\frac{3 \sqrt{-a} \cosh \left (c+\frac{\sqrt{-a} d}{\sqrt{b}}\right ) \text{Chi}\left (\frac{\sqrt{-a} d}{\sqrt{b}}-d x\right )}{4 b^{5/2}}-\frac{3 \sqrt{-a} \cosh \left (c-\frac{\sqrt{-a} d}{\sqrt{b}}\right ) \text{Chi}\left (\frac{\sqrt{-a} d}{\sqrt{b}}+d x\right )}{4 b^{5/2}}-\frac{a d \text{Chi}\left (\frac{\sqrt{-a} d}{\sqrt{b}}+d x\right ) \sinh \left (c-\frac{\sqrt{-a} d}{\sqrt{b}}\right )}{4 b^3}-\frac{a d \text{Chi}\left (\frac{\sqrt{-a} d}{\sqrt{b}}-d x\right ) \sinh \left (c+\frac{\sqrt{-a} d}{\sqrt{b}}\right )}{4 b^3}+\frac{\sinh (c+d x)}{b^2 d}+\frac{a d \cosh \left (c+\frac{\sqrt{-a} d}{\sqrt{b}}\right ) \text{Shi}\left (\frac{\sqrt{-a} d}{\sqrt{b}}-d x\right )}{4 b^3}-\frac{3 \sqrt{-a} \sinh \left (c+\frac{\sqrt{-a} d}{\sqrt{b}}\right ) \text{Shi}\left (\frac{\sqrt{-a} d}{\sqrt{b}}-d x\right )}{4 b^{5/2}}-\frac{a d \cosh \left (c-\frac{\sqrt{-a} d}{\sqrt{b}}\right ) \text{Shi}\left (\frac{\sqrt{-a} d}{\sqrt{b}}+d x\right )}{4 b^3}-\frac{3 \sqrt{-a} \sinh \left (c-\frac{\sqrt{-a} d}{\sqrt{b}}\right ) \text{Shi}\left (\frac{\sqrt{-a} d}{\sqrt{b}}+d x\right )}{4 b^{5/2}}\\ \end{align*}
Mathematica [C] time = 1.50657, size = 621, normalized size = 1.38 \[ \frac{-\frac{3 \sqrt{a} \sinh (c) \left (\sin \left (\frac{\sqrt{a} d}{\sqrt{b}}\right ) \text{CosIntegral}\left (-\frac{\sqrt{a} d}{\sqrt{b}}+i d x\right )+\sin \left (\frac{\sqrt{a} d}{\sqrt{b}}\right ) \text{CosIntegral}\left (\frac{\sqrt{a} d}{\sqrt{b}}+i d x\right )-\cos \left (\frac{\sqrt{a} d}{\sqrt{b}}\right ) \left (\text{Si}\left (\frac{\sqrt{a} d}{\sqrt{b}}-i d x\right )+\text{Si}\left (i x d+\frac{\sqrt{a} d}{\sqrt{b}}\right )\right )\right )}{\sqrt{b}}-\frac{a d \sinh (c) \left (\cos \left (\frac{\sqrt{a} d}{\sqrt{b}}\right ) \text{CosIntegral}\left (-\frac{\sqrt{a} d}{\sqrt{b}}+i d x\right )+\cos \left (\frac{\sqrt{a} d}{\sqrt{b}}\right ) \text{CosIntegral}\left (\frac{\sqrt{a} d}{\sqrt{b}}+i d x\right )+\sin \left (\frac{\sqrt{a} d}{\sqrt{b}}\right ) \left (\text{Si}\left (\frac{\sqrt{a} d}{\sqrt{b}}-i d x\right )+\text{Si}\left (i x d+\frac{\sqrt{a} d}{\sqrt{b}}\right )\right )\right )}{b}-\frac{3 i \sqrt{a} \cosh (c) \left (\cos \left (\frac{\sqrt{a} d}{\sqrt{b}}\right ) \text{CosIntegral}\left (-\frac{\sqrt{a} d}{\sqrt{b}}+i d x\right )-\cos \left (\frac{\sqrt{a} d}{\sqrt{b}}\right ) \text{CosIntegral}\left (\frac{\sqrt{a} d}{\sqrt{b}}+i d x\right )+\sin \left (\frac{\sqrt{a} d}{\sqrt{b}}\right ) \left (\text{Si}\left (\frac{\sqrt{a} d}{\sqrt{b}}-i d x\right )-\text{Si}\left (i x d+\frac{\sqrt{a} d}{\sqrt{b}}\right )\right )\right )}{\sqrt{b}}+\frac{i a d \cosh (c) \left (\sin \left (\frac{\sqrt{a} d}{\sqrt{b}}\right ) \text{CosIntegral}\left (-\frac{\sqrt{a} d}{\sqrt{b}}+i d x\right )-\sin \left (\frac{\sqrt{a} d}{\sqrt{b}}\right ) \text{CosIntegral}\left (\frac{\sqrt{a} d}{\sqrt{b}}+i d x\right )+\cos \left (\frac{\sqrt{a} d}{\sqrt{b}}\right ) \left (\text{Si}\left (i x d+\frac{\sqrt{a} d}{\sqrt{b}}\right )-\text{Si}\left (\frac{\sqrt{a} d}{\sqrt{b}}-i d x\right )\right )\right )}{b}+2 \cosh (d x) \left (\frac{a x \cosh (c)}{a+b x^2}+\frac{2 \sinh (c)}{d}\right )+2 \sinh (d x) \left (\frac{a x \sinh (c)}{a+b x^2}+\frac{2 \cosh (c)}{d}\right )}{4 b^2} \]
Warning: Unable to verify antiderivative.
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Maple [A] time = 0.319, size = 532, normalized size = 1.2 \begin{align*}{\frac{{d}^{2}{{\rm e}^{-dx-c}}ax}{4\,{b}^{2} \left ( b{d}^{2}{x}^{2}+a{d}^{2} \right ) }}-{\frac{3\,a}{8\,{b}^{2}}{{\rm e}^{{\frac{1}{b} \left ( d\sqrt{-ab}-cb \right ) }}}{\it Ei} \left ( 1,{\frac{1}{b} \left ( d\sqrt{-ab}+ \left ( dx+c \right ) b-cb \right ) } \right ){\frac{1}{\sqrt{-ab}}}}+{\frac{3\,a}{8\,{b}^{2}}{{\rm e}^{-{\frac{1}{b} \left ( d\sqrt{-ab}+cb \right ) }}}{\it Ei} \left ( 1,-{\frac{1}{b} \left ( d\sqrt{-ab}- \left ( dx+c \right ) b+cb \right ) } \right ){\frac{1}{\sqrt{-ab}}}}-{\frac{{{\rm e}^{-dx-c}}}{2\,d{b}^{2}}}-{\frac{da}{8\,{b}^{3}}{{\rm e}^{{\frac{1}{b} \left ( d\sqrt{-ab}-cb \right ) }}}{\it Ei} \left ( 1,{\frac{1}{b} \left ( d\sqrt{-ab}+ \left ( dx+c \right ) b-cb \right ) } \right ) }-{\frac{da}{8\,{b}^{3}}{{\rm e}^{-{\frac{1}{b} \left ( d\sqrt{-ab}+cb \right ) }}}{\it Ei} \left ( 1,-{\frac{1}{b} \left ( d\sqrt{-ab}- \left ( dx+c \right ) b+cb \right ) } \right ) }+{\frac{{{\rm e}^{dx+c}}}{2\,d{b}^{2}}}+{\frac{{d}^{2}{{\rm e}^{dx+c}}ax}{4\,{b}^{2} \left ( b{d}^{2}{x}^{2}+a{d}^{2} \right ) }}+{\frac{3\,a}{8\,{b}^{2}}{{\rm e}^{{\frac{1}{b} \left ( d\sqrt{-ab}+cb \right ) }}}{\it Ei} \left ( 1,{\frac{1}{b} \left ( d\sqrt{-ab}- \left ( dx+c \right ) b+cb \right ) } \right ){\frac{1}{\sqrt{-ab}}}}-{\frac{3\,a}{8\,{b}^{2}}{{\rm e}^{-{\frac{1}{b} \left ( d\sqrt{-ab}-cb \right ) }}}{\it Ei} \left ( 1,-{\frac{1}{b} \left ( d\sqrt{-ab}+ \left ( dx+c \right ) b-cb \right ) } \right ){\frac{1}{\sqrt{-ab}}}}+{\frac{da}{8\,{b}^{3}}{{\rm e}^{{\frac{1}{b} \left ( d\sqrt{-ab}+cb \right ) }}}{\it Ei} \left ( 1,{\frac{1}{b} \left ( d\sqrt{-ab}- \left ( dx+c \right ) b+cb \right ) } \right ) }+{\frac{da}{8\,{b}^{3}}{{\rm e}^{-{\frac{1}{b} \left ( d\sqrt{-ab}-cb \right ) }}}{\it Ei} \left ( 1,-{\frac{1}{b} \left ( d\sqrt{-ab}+ \left ( dx+c \right ) b-cb \right ) } \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [B] time = 2.31252, size = 2488, normalized size = 5.54 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{x^{4} \cosh \left (d x + c\right )}{{\left (b x^{2} + a\right )}^{2}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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